cement quantity for plastering|plastering ratio of cement and sand calculation
cement quantity for plastering|plastering ratio of cement and sand calculation
Estimate for plastering Work
scroll down and download pdf
EXAMPLE
Plaster Area = Length × Width
Plaster Area =10×10
Plaster Area = 100.00 m 2
Plaster Area = 1076.39 ft 2
Step 1:
Volume Of Mortar = Plaster Area × Plaster Thickness In Meter
Volume Of Mortar = 100.00 × 0.012
Volume Of Mortar = 1.20 m 3
Note: Add 30% to fill up join & Cover surface
Volume Of Mortar = 1.20 + ( 1.20 × 0.3 )
Volume Of Mortar =1.56m3
Note: Increases by 25% of the total dry volume
Dry Volume Of Mortar =1.56+1.56×0.25
Dry Volume Of Mortar = 1.95 m 3
Step 2:
Amount of Cement Require = ( D r y V o l u m e × C e m e n t R a t i o S u m o f R a t i o ) ÷ Volume of Cement Bag
= ( 1.95 × 1 4 ) ÷ 0 . 035 1.95 × 14 ÷ 0.035
No. of Cement Bag Require = 13.93 Bags
Require Cement in Kg = 696.43 kg.
Note: 1 Bag of cement = 0.035 m3.
1 Cement bag contains = 50 kg cement.
Step 3:
Quantity of Sand Require = ( D r y V o l u m e × Sand R a t i o S u m o f R a t i o ) × Density of Sand
= ( 1.95 × 3 4 ) × 1550
Qauntity of Sand require : 2267 Kg
Quantity of Sand require: 2.27 Ton
Note: By considering the dry density of sand = 1550 kg/m3. 1000 kg = 1 Ton
👇PDF Format download👇
DOWNLOAD ALL SIZE PLAN
RESIDENTIAL PLAN
#1 (40' x 80') - Click here
#2 (30' x 50') - Click here
#3 (30' x 24') - Click here
#4 (30' x 60') - Click here
#5 (30' x 70') - Click here
#6 (25' x 60') - Click here
#7 (20' x 60') - Click here
#8 (30' x 40') - Click here
COMMENTS